%% Plotting the solution of the heat equation as a function of x and t
%%
% Here are two ways you can use MATLAB to produce the plot in Figure
% 10.5.5 of Boyce and DiPrima.  In Example 1 of Section 10.5, the solution
% has been found to be be 
% 
% $$u(x,t)= \frac {80}\pi \sum _{n=1,3,5,...}^\infty \frac 1n\, e^{\mbox{--} n^2 
% \pi ^2 \alpha ^2 t/2500} \, \sin \frac {n\pi x}{50}.$$
% 
% For the plot, take $\alpha^2=1$.  
%% First method, defining the partial sums symbolically and using ezsurf
%
% Unfortunately, I haven't figured out how to get ezsurf to do the graph in
% a reasonable amount of time using an anonymous function (the kind defined
% with @) but an inline function works.  
syms x t n
u = inline((80/pi)*symsum(exp(-(2*n-1)^2*pi^2*t/2500)*sin((2*n-1)*pi*x/50)/(2*n-1),n,1,20));
ezsurf(u,[0 250 0 50])
title('')

%% Second method, using surf
%
% I start by defining the grid of x and t values where the values of u will
% be computed.  Be careful not to use too many points in your meshgrid
% command; if you do you won't get a clear plot.

x = linspace(0,50,50); t = linspace(0,250,100); [X,T]= meshgrid(x,t);

%%
% Alternatively, I could create the meshgrid by giving the command

[X,T]= meshgrid(0:1:50,0:2.5:250);
%%
% Next I define u using a *for* loop to add terms, starting with u=0.

u=0;
for n=1:20
    u = u + exp(-(2.*n-1).^2.*pi.^2.*T./2500).*sin((2.*n-1).*pi.*X./50)./(2.*n-1);
end
%%
surf(T,X,u)