SAMPLE PROBLEM 13.6
Using Raoult’s Law to find the vapor pressure lowering
SOLUTION:
10.0 mL C3H8O3
= 0.137 mol C3H8O3
500.0 mL H2O
= 27.4 mol H2O
DP =
0.137 mol C3H8O3
0.137 mol C3H8O3 + 27.4 mol H2O
92.5 torr
x
x
x
= 0.461 torr
x
x
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