rate 3 k[O2]3m[NO]3n
rate 1 k[O2]1m[NO]1n
=
([O2] is held constant)
via same manipulations as before:
3.99 = (2.00)n
n = 2
Thus, the reaction is second order with respect to NO.
When [NO] doubles, the rate quadruples.
The rate law is: rate = k[O2][NO]2
The reaction is third order overall.
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