Sample Problem 17.10
(continued)
Qc of 64 is >> than Kc = 0.036
The reaction will progress to the left.
initial
change
equilibrium
4.00
8.00
4.00
8.00
+ x
+ 2x
- 4x
4.00 + x
8.00 + 2x
- x
4.00 - x
8.00 - 4x
At equilibrium [CH4] = 5.56 M, so 5.56 = 4.00 + x; thus, x = 1.56 M
Therefore:
[H2S] = 8.00 + 2x = 11.12 M
[CS2] = 4.00 - x = 2.44 M
[H2] = 8.00 - 4x = 1.76 M
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