Sample Problem 17.11
(continued)
(b) When O2 is added, Q decreases and the reaction progresses to the right to come back to K. Thus, [H2S] decreases.
(c) When H2S is removed, Q increases and the reaction progresses to the left to come back to K. Thus, [O2] increases.
(d) Sulfur is not part of the Q (or K) expression because it is a solid. Therefore, as long as some sulfur is present, the reaction is unaffected. [H2S] is unchanged.
2H2S(g) + O2(g) 2S(s) + 2H2O(g)
| Previous slide | Next slide | Back to first slide | View graphic version |