SAMPLE PROBLEM 18.8
(continued)
concentration (M)
Ka1 = [HAsc-][H3O+]/[H2Asc] = 1.0 x 10-5 = (x)(x)/0.050 M
pH = -log(7.1 x 10-4) = 3.15
HAsc-(aq) + H2O(l) Asc2-(aq) + H3O+(aq)
7.1 x 10-4
-
0
0
equilibrium
7.1 x 10-4 - x
-
x
x
initial
x
x = 7.1 x 10-4 M = [HAsc-]
concentration (M)
x = [(7.1 x 10-4)(5 x 10-12)]0.5
= 6 x 10-8 M = [H3O+]
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