Sample Problem 19.1
(continued)
[CH3COOH]eq 0.50 M
[CH3COO-]eq 0.50 M
[H3O+] = x
Ka =
= 1.8 x 10-5 M
Check the assumption:
1.8 x 10-5/0.50 X 100 = 3.6 x 10-3 %
before addition
addition
after addition
= 0.020 M NaOH
0.50
-
0.50
-
-
-
-
0.020
-
0.48
0
0.52
___________________________________________________________
pH = 4.74
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