Sample Problem 19.10
(continued)
initial
change
equilibrium
1.3 x 10-3
5.0 x 10-2
0
-
~(-1.3 x 10-3)
~(-5.2 x 10-3)
Since we assume that all of the Zn(H2O)42+ has reacted, it would consume four times its amount in NH3..
[NH3]used = 4 (1.3 x 10-3 M) = 5.2 x 10-3 M
~(+1.3 x 10-3)
-
x
4.5 x 10-2
1.3 x 10-3
[Zn(H2O)42+]remaining = x (a very small amount)
-
x = 4.1 x 10-7 M
_____________________________________________________________
A result of the
very large Kf!
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