Sample Problem 19.12
Separating ions by selective precipitation
SOLUTION:
Cu(OH)2 will precipitate first (it has the smaller Ksp) so we calculate the [OH-] needed for a saturated solution of Mg(OH)2. This will ensure that we do not precipitate Mg(OH)2. We can then check how much Cu2+ remains in solution.
[OH-] needed for a saturated Mg(OH)2 solution =
= 5.6 x 10-5 M
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