Calculating the Mass of an Element in a Compound
Ammonium Nitrate
ammonium nitrate = NH4NO3
How much nitrogen (N) is found in 455 kg of ammonium nitrate?
The formula mass of cpd is:
4 x H = 4 x 1.008 = 4.032 g
2 x N = 2 x 14.01 = 28.02 g
3 x O = 3 x 16.00 = 48.00 g
Therefore g nitrogen/g cpd
455 kg x 1000 g/kg = 455,000 g NH4NO3
455,000 g cpd x 0.3500 g N/g cpd = 1.59 x 105 g nitrogen
or:
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