Sample Problem 20.7
(continued)
(b) The value of Q =
= 4.00
Since Q is < K at both temperatures the reaction will shift right; for 298 K there will be a dramatic shift while at 973 K the shift will be slight.
(c) The non-standard DG is calculated using DG = DGo + RTlnQ
DG298 = -141.6 kJ/mol + (8.314 J/mol.K)(kJ/103J)(298 K)(ln 4.00)
DG298 = -138.2 kJ/mol
DG973 = -12.12 kJ/mol + (8.314 J/mol.K)(kJ/103J)(973 K)(ln 4.00)
DG298 = -0.9 kJ/mol
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