Balancing redox reactions in acidic solution
Cr2O72-(aq) + I-(aq) Cr3+(aq) + I2(aq)
1. Divide the reaction into half-reactions
Determine ONs for the species undergoing redox.
+6
-1
+3
0
2. Balance atoms and charges in each half-reaction
2
+ 7H2O(l)
14H+(aq) +
Cr is going from +6 to +3
I is going from -1 to 0
net: +12
net: +6
Add 6 e- to left.
| Previous slide | Next slide | Back to first slide | View graphic version |