Sample Problem 21.9
Predicting the electrolysis products of aqueous ionic solutions
SOLUTION:
The reduction half-reaction with the less negative potential, and the oxidation half-reaction with the less positive potential will occur at their respective electrodes.
The overvoltage would make the water reduction -0.82 to -1.02 but the reduction of K+ is still a higher potential so H2(g) is produced at the cathode.
The overvoltage would give the water half-cell more potential than the Br-, so the Br- will be oxidized. Br2(g) forms at the anode.
Previous slide | Next slide | Back to first slide | View graphic version |