SOLUTION:
There are 12.01 g C per mol CO2
1.50 g CO2 x
= 0.409 g C
0.41 g H2O x
= 0.046 g H
There are 2.016 g H per mol H2O
O must be the difference: 1.000 g - (0.409 + 0.046) = 0.545
= 0.0341 mol C
= 0.0461 mol H
= 0.0341 mol O
C1H1.3O1
C3H4O3
= 2.000
C6H8O6
Sample Problem 3.6
(continued)
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