Sample Problem 3.13
Calculating Mass of Solute in a Given Volume of Solution
PROBLEM:
How many grams of solute are found in 1.75 L of a 0.460 M solution of sodium monohydrogen phosphate?
volume of soln
moles of solute
grams of solute
multiply by M
multiply by M
PLAN:
SOLUTION:
Molarity is the number of moles of solute per liter of solution. Knowing the molarity and volume allows us to find the number of moles and then the number of grams of solute. The molecular formula of the solute is Na2HPO4.
1.75 L
0.805 mol Na2HPO4
= 0.805 mol Na2HPO4
= 114 g Na2HPO4
x
x
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