PPT Slide

SOLUTION:

Sample Problem 3.16

(continued)

0.050 L Hg(NO3)2

x 0.010 mol/L x

0.020 L Na2S

x 0. 10 mol/L x

= 5.0 x 10-4 mol HgS

= 2.0 x 10-3 mol HgS

Hg(NO3)2 is the limiting reagent.

5.0 x 10-4 mol HgS x

= 0.12 g HgS