Sample Problem 4.5
Finding the Concentration of Acid from an Acid-Base Titration
PROBLEM:
You perform an acid-base titration to standardize an HCl solution by placing 50.00 mL of HCl in a flask with a few drops of indicator solution. You put 0.1524 M NaOH into a buret, and the initial reading is 0.55 mL. At the end-point, the buret reads 33.
PLAN:
SOLUTION:
volume(L) of base
mol of base
mol of acid
M of acid
multiply by M of base
molar ratio
divide by L of acid
NaOH(aq) + HCl(aq) NaCl(aq) + H2O(l)
(33.87-0.55) mL x
= 0.03332 L
0.03332 L
x 0.1524 M
= 5.078 x 10-3 mol NaOH
Molar ratio is 1:1
= 0.1016 M HCl
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