Sample Problem 5.2
Applying the Volume-Pressure Relationship
PLAN:
SOLUTION:
V1 in cm3
V1 in mL
V1 in L
V2 in L
P1 = 1.12 atm
P2 = 2.64 atm
V1 = 24.8 cm3
V2 = unknown
n and T are constant
24.8 cm3
= 0.0248 L
=
P1V1 = P2V2
P1V1
P2
1 cm3 = 1 mL
103 mL = 1 L
x P1/P2
or
x
x
x
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