Sample Problem 5.11
Using the Ideal Gas Law in a Limiting Reactant Problem
SOLUTION:
n =
Cl2
x
5.25 L
= 0.414 mol
KCl formed
0.435 mol K x
= 0.435 mol
KCl formed
Cl2 is the limiting reactant
0.414 mol KCl x
= 30.9 g KCl
=
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