Laurie B. answered • 04/21/20

Professor Laurie

Knowing a^{2 } + b^{2} = c^{2}, where a and b are the legs and c is the hypotenuse.

Let a = 6 and c = 8

It does not matter if a or b equals 6 since they are both legs.

6^{2} + b^{2} = 8^{2}

36 + b^{2 } = 64

Get the variable alone to solve for b by adding the opposite to both sides:

b^{2} = 64 - 36

b^{2} = 28

Take the square root of both sides: approximately 5.3

Or, find the largest perfect square of 28 which is 4 times 7. Since 7 is not a perfect square and 4 is because 2×2 makes 4, your other possible answer is 2 times the square root of 7.

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Laurie B.

Sorry can't make the radical sign with my phone04/21/20