Example 3.2


Return to the main page.
    Consider the system f(x,y) = {x2 + y2 - 1, x + y2 - 1} with Newton-invariant set x - y - 1 = 0. We construct the randomized system gR(x,y) = {x2 + y2 - 1 + 2(x - y - 1), x + y2 - 1 + 3(x - y - 1)} and take start points (1/250,-249/250) and (251/250,-1/250). Since both quadratically converge to solutions of gR = 0 and start on this Newton-invariant set, Theorem 3.1 yields the limit points are indeed solutions of f = 0. Note that one of the solutions, namely (1,0), is a singular solution with respect to f.

The remainder of this page documents this computation.
Directions
Before you begin, you will need to have a working version of alphaCertified.
Return to the main page.