
\magnification1200\footline{}
\centerline{\bf Math.~126 Quiz \#6}
\centerline{March 2, 1999}
\vskip10pt
\def\frac#1#2{{{\textstyle#1}\over{\textstyle#2}}}
Expand $$\frac{3x^2-2x+3}{(x^2-1)(x^2+1)}$$
as a partial fraction.
Then evaluate
 $$\int \frac{3x^2-2x+3}{(x^2-1)(x^2+1)}\>dx\ .$$

\end

Sent Mon Mar 1 06:42:37 EST 1999
