(************** Content-type: application/mathematica ************** Mathematica-Compatible Notebook This notebook can be used with any Mathematica-compatible application, such as Mathematica, MathReader or Publicon. The data for the notebook starts with the line containing stars above. To get the notebook into a Mathematica-compatible application, do one of the following: * Save the data starting with the line of stars above into a file with a name ending in .nb, then open the file inside the application; * Copy the data starting with the line of stars above to the clipboard, then use the Paste menu command inside the application. Data for notebooks contains only printable 7-bit ASCII and can be sent directly in email or through ftp in text mode. Newlines can be CR, LF or CRLF (Unix, Macintosh or MS-DOS style). 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For more information on notebooks and Mathematica-compatible applications, contact Wolfram Research: web: http://www.wolfram.com email: info@wolfram.com phone: +1-217-398-0700 (U.S.) Notebook reader applications are available free of charge from Wolfram Research. *******************************************************************) (*CacheID: 232*) (*NotebookFileLineBreakTest NotebookFileLineBreakTest*) (*NotebookOptionsPosition[ 8731, 284]*) (*NotebookOutlinePosition[ 9362, 306]*) (* CellTagsIndexPosition[ 9318, 302]*) (*WindowFrame->Normal*) Notebook[{ Cell[CellGroupData[{ Cell["Winding Numbers", "Subsection"], Cell[CellGroupData[{ Cell["Example", "Subsubsection"], Cell[TextData[{ "Calculate the winding number of the image of circles of radii 1/2, 1 and 2 \ under the map ", Cell[BoxData[ \(TraditionalForm\`f(z)\ = \ \((z\^3 + 2)\)/z\)]], "." }], "Text"] }, Open ]], Cell[CellGroupData[{ Cell["Solution ", "Subsubsection"], Cell[TextData[{ "The winding number equals the number of zeros ", Cell[BoxData[ \(TraditionalForm\`-\)]], " the number of poles inside the curve. The zeros of ", Cell[BoxData[ \(TraditionalForm\`f(z)\)]], " are the cube roots of ", Cell[BoxData[ \(TraditionalForm\`\(-2\)\)]], ". Since," }], "Text"], Cell[BoxData[ \(N[\@2\%3]\)], "Input"], Cell[TextData[{ "all three zeros lie inside the circle of radius 2, but none lie inside the \ circles of radii 1/2 or 1. ", Cell[BoxData[ \(TraditionalForm\`f(z)\)]], " has a simple pole at the origin which lies in all three circles.\n\ Therefore, the winding numbers for the images of the circles of radii 1/2 and \ 1 are both ", Cell[BoxData[ \(TraditionalForm\`0 - 1 = \(-1\)\)]], ". The winding number for the image of the circle of radius 2 is ", Cell[BoxData[ \(TraditionalForm\`3\ - \ 1\ = \ 2\)]], ".\nHere are some graphical representations." }], "Text"], Cell[BoxData[{ \(\(z\ = \ x\ + \ I\ y;\)\), "\n", \(u = Re[\((z\^3\ + \ 2)\)/z] // ComplexExpand; \), "\n", \(\(v = Im[\((z\^3\ + \ 2)\)/z] // ComplexExpand;\)\), "\n", \(x\ = \ r\ Cos[t]; \ y\ = \ r\ Sin[t];\)}], "Input"], Cell[TextData[{ StyleBox["The image of thecircle of radius 1/2", FontSlant->"Italic"], " (animate the graphic by selecting it and pressingCTRL-Y)." }], "Text"], Cell[BoxData[{ \(\(r\ = .5;\)\), "\[IndentingNewLine]", \(Do[ParametricPlot[{u, v}, {t, 0, p}, PlotRange \[Rule] {{\(-5\), 5}, {\(-5\), 5}}], {p, \[Pi]/4, 2 \[Pi], \[Pi]/4}]\)}], "Input"], Cell[TextData[{ "The curve circles the origin counterclockwise once, so the winding number \ is ", Cell[BoxData[ \(TraditionalForm\`\(-1\)\)]], ".\n\n", StyleBox["The image of the circle of radius 1.", FontSlant->"Italic"] }], "Text"], Cell[BoxData[{ \(\(r\ = 1;\)\), "\[IndentingNewLine]", \(Do[ParametricPlot[{u, v}, {t, 0, p}, PlotRange \[Rule] {{\(-5\), 5}, {\(-5\), 5}}], {p, \[Pi]/4, 2 \[Pi], \[Pi]/4}]\)}], "Input"], Cell[TextData[{ "The curve still circles the origin counterclockwise once, so the winding \ number is ", Cell[BoxData[ \(TraditionalForm\`\(-1\)\)]], ".\n\n", StyleBox["The image of the circle of radius 2.", FontSlant->"Italic"] }], "Text"], Cell[BoxData[{ \(\(r\ = 2;\)\), "\[IndentingNewLine]", \(Do[ParametricPlot[{u, v}, {t, 0, p}, PlotRange \[Rule] {{\(-5\), 5}, {\(-5\), 5}}], {p, \[Pi]/4, 2 \[Pi], \[Pi]/4}]\)}], "Input"], Cell[TextData[{ "Now the curve circles the origin twice in a counter-clockwise direction, \ so the winding number is 2.\nNext are images of the circles of ", Cell[BoxData[ \(TraditionalForm\`r\ = \ \ 1/2\)]], " to 2 in steps of .1. You can see parts of the curve cross over the origin \ when ", Cell[BoxData[ \(TraditionalForm\`r\)]], " passes through the cube root of 2, changing the winding number from ", Cell[BoxData[ \(TraditionalForm\`\(-1\)\)]], " to 2." }], "Text"], Cell[BoxData[ \(Do[ParametricPlot[{u, v}, {t, 0, 2 \[Pi]}, PlotRange \[Rule] {{\(-5\), 5}, {\(-5\), 5}}], {r, .5, 2, .1}]\)], "Input"] }, Open ]], Cell[CellGroupData[{ Cell["Example", "Subsubsection"], Cell[TextData[{ "Calculate the winding number of the image of circles of radii 1/4 and 1 \ under the map ", Cell[BoxData[ \(TraditionalForm\`f(z)\ = \ \((2 z - 1)\)\^7/z\^3\)]], "." }], "Text"] }, Open ]], Cell[CellGroupData[{ Cell["Solution ", "Subsubsection"], Cell[TextData[{ "The winding number equals the number of zeros ", Cell[BoxData[ \(TraditionalForm\`-\)]], " the number of poles inside the curve. ", Cell[BoxData[ \(TraditionalForm\`f(z)\)]], " has a zero of order 7 at ", Cell[BoxData[ \(TraditionalForm\`1/2\)]], ", and a pole of order three at the origin. Therefore, the winding number \ of the image of the circle of radius 1/4 is ", Cell[BoxData[ \(TraditionalForm\`0 - 3 = \(-3\)\)]], ", and the winding number of the image of the circle of radius 1 is ", Cell[BoxData[ \(TraditionalForm\`7 - 3 = 4\)]], "." }], "Text"], Cell["Here are some graphical representations.", "Text"], Cell[BoxData[{ \(\(z\ = \ x\ + \ I\ y;\)\), "\n", \(u = Re[\((2 z - 1)\)\^7/z\^3] // ComplexExpand; \), "\n", \(\(v = Im[\((2 z - 1)\)\^7/z\^3] // ComplexExpand;\)\), "\n", \(x\ = \ r\ Cos[t]; \ y\ = \ r\ Sin[t];\)}], "Input"], Cell[TextData[{ StyleBox["The image of the circle of radius 1/4.", FontSlant->"Italic"], "\nThe start of the curve shows that it is moving clockwise." }], "Text"], Cell[BoxData[{ \(\(r\ = .25;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, \[Pi]/2}, PlotRange \[Rule] {{\(-15\), 10}, {\(-5\), 5}}]\)}], "Input"], Cell["The curve wraps around twice near the origin:", "Text"], Cell[BoxData[{ \(\(r\ = .25;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, 2 \[Pi]}, PlotRange \[Rule] {{\(-15\), 10}, {\(-5\), 5}}]\)}], "Input"], Cell["and once more much further away:", "Text"], Cell[BoxData[{ \(\(r\ = 1;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, 2 \[Pi]}, PlotRange \[Rule] {{\(-500\), 2500}, {\(-1500\), 1500}}]\)}], "Input"], Cell[TextData[{ "Thus, the winding number is ", Cell[BoxData[ \(TraditionalForm\`\(-3\)\)]], ".\n\n", StyleBox["The image of the circle of radius 1.", FontSlant->"Italic"], "\nThe start of the curve shows that it is moving counter-clockwise." }], "Text"], Cell[BoxData[{ \(\(r\ = 1;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, \[Pi]/2}, PlotRange \[Rule] {{\(-10\), 15}, {\(-5\), 5}}]\)}], "Input"], Cell["The curve wraps around twice near the origin:", "Text"], Cell[BoxData[{ \(\(r\ = 1;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, 2 \[Pi]}, PlotRange \[Rule] {{\(-10\), 15}, {\(-5\), 5}}]\)}], "Input"], Cell["once more further away:", "Text"], Cell[BoxData[{ \(\(r\ = 1;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, 2 \[Pi]}, PlotRange \[Rule] {{\(-300\), 100}, {\(-100\), 100}}]\)}], "Input"], Cell["and a final loop very far from the origin:", "Text"], Cell[BoxData[{ \(\(r\ = 1;\)\), "\[IndentingNewLine]", \(ParametricPlot[{u, v}, {t, 0, 2 \[Pi]}, PlotRange \[Rule] {{\(-500\), 2500}, {\(-1500\), 1500}}]\)}], "Input"], Cell["Thus, the total winding number is 4.", "Text"] }, Open ]] }, Open ]] }, FrontEndVersion->"4.1 for X", ScreenRectangle->{{0, 1280}, {0, 1024}}, WindowSize->{520, 600}, WindowMargins->{{Automatic, 169}, {Automatic, 76}} ] (******************************************************************* Cached data follows. 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