Sample Problem 19.9
Predicting whether a precipitate will form
mol Ca2+ = 0.100 L(0.30 mol/L) = 0.030 mol
[Ca2+] = 0.030 mol/0.300 L = 0.10 M
mol F- = 0.200 L(0.060 mol/L) = 0.012 mol
[F-] = 0.012 mol/0.300 L = 0.040 M
Q = [Ca2+][F-]2 =
(0.10)(0.040)2 = 1.6 x 10-4
Q is >> Ksp, thus CaF2 will precipitate.
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